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Solutions and Answers to Selected Problems
| Content Provider | Scilit |
|---|---|
| Author | Petrovic, John |
| Copyright Year | 2013 |
| Description | Section 1.3 1.3.3. Hint: Write an+1 − an as (an+1 − L)− (an − L). Consider an = √ n. 1.3.5. Let ε = L+ 12 (1− L). Then, there exists n ∈ N such that, if n ≥ N , an+1 an ≤ L+ ε < 1. By induction, prove that 0 ≤ aN+k ≤ aN (1 + ε)k. Since the right side goes to 0, we obtain that lim an = 0. Book Name: Advanced Calculus |
| Related Links | https://content.taylorfrancis.com/books/download?dac=C2012-0-03995-1&isbn=9780429099748&doi=10.1201/b15969-19&format=pdf |
| Ending Page | 554 |
| Page Count | 78 |
| Starting Page | 477 |
| DOI | 10.1201/b15969-19 |
| Language | English |
| Publisher | Informa UK Limited |
| Publisher Date | 2013-11-01 |
| Access Restriction | Open |
| Subject Keyword | Book Name: Advanced Calculus Answers To Selected Selected Problems Section |
| Content Type | Text |
| Resource Type | Chapter |
