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Entropy Example # 3
| Content Provider | AK Lectures |
|---|---|
| Description | Recall that according to the Second Law of Thermodynamics, the total change in entropy of any isolated system will always be greater than zero. In this example, we would like to determine the change in entropy of the system (the metal) as well as calculate the change in entropy of the surroundings (large body of water). The sum of these two quantities according to the Second Law of Thermodynamics must be greater than zero. Since the temperature of the system (the metal) is not constant, to determine the change in entropy we must take the integral of the infinitesimal change in entropy from state 1 to state 2. For the second part, since the temperature of the large body of water is assumed to be constant, we can simply divide the energy that is transferred into the water by the temperature. |
| Language | English |
| Access Restriction | Open |
| Subject Keyword | Classical Physics Thermodynamics entropy system change temperature metal Second Law body water |
| Content Type | Video |
| Educational Role | Teacher Student |
| Educational Use | Self Learning Lecture Reading |
| Resource Type | Video Lecture |
| Education Level | Under Graduate |
| Subject | Heat |
